Thread:Corbierr/@comment-18063949-20140505165348/@comment-18063949-20140505211409

Ohh, okay, right.

Okay so what we’re going to do first is take a look at the different properties we can use when doing these equations: So if we have b log ac it also equals logac^b If we have logab - logac it equals loga(b/c)

Applying this to the problem we have here: log10(3x-2)=4log102

Step 1, Distribute log10(3x-2): log103x- log102

Step 2, Simplify 4log102: log10(2)^4

Then, the equation would be: log103x- log102= log10(2)^4

Step 3, use the equation logab - loga(b/c) to simplify log103x- log102: log10(3x/2)

The equation now is: log10(3x/2) = log10(2)^4

Therefore, since we have log10 on both sides, the equation simplifies to: 3x/2 = 2^4

3x/2 = 16

(multiply by 2 on both sides)

3x=32

x=32/3

Chances are I got this totally wrong and so sorry if I did. Also, sorry it’s a kind of long post… and I think I did a terrible job explaining it… :P